33(8j-11)=5(7j+5)

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Solution for 33(8j-11)=5(7j+5) equation: 



33(8j-11)=5(7j+5)

We move all terms to the left:

33(8j-11)-(5(7j+5))=0

We multiply parentheses

264j-(5(7j+5))-363=0



We calculate terms in parentheses: -(5(7j+5)), so:

5(7j+5)

We multiply parentheses

35j+25

Back to the equation:

-(35j+25)



We get rid of parentheses

264j-35j-25-363=0

We add all the numbers together, and all the variables

229j-388=0

We move all terms containing j to the left, all other terms to the right

229j=388

j=388/229

j=1+159/229

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