33+(2t-50)+(2t-11)=180

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Solution for 33+(2t-50)+(2t-11)=180 equation: 



33+(2t-50)+(2t-11)=180

We move all terms to the left:

33+(2t-50)+(2t-11)-(180)=0

We add all the numbers together, and all the variables

(2t-50)+(2t-11)-147=0

We get rid of parentheses

2t+2t-50-11-147=0

We add all the numbers together, and all the variables

4t-208=0

We move all terms containing t to the left, all other terms to the right

4t=208

t=208/4

t=52

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