33+3y-10=13y-12-3y

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Solution for 33+3y-10=13y-12-3y equation: 



33+3y-10=13y-12-3y

We move all terms to the left:

33+3y-10-(13y-12-3y)=0

We add all the numbers together, and all the variables

3y-(10y-12)+33-10=0

We add all the numbers together, and all the variables

3y-(10y-12)+23=0

We get rid of parentheses

3y-10y+12+23=0

We add all the numbers together, and all the variables

-7y+35=0

We move all terms containing y to the left, all other terms to the right

-7y=-35

y=-35/-7

y=+5

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