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33-(2c+3)=2(c+5)+2c
We move all terms to the left:
33-(2c+3)-(2(c+5)+2c)=0
We get rid of parentheses
-2c-(2(c+5)+2c)-3+33=0
We calculate terms in parentheses: -(2(c+5)+2c), so:We add all the numbers together, and all the variables
2(c+5)+2c
We add all the numbers together, and all the variables
2c+2(c+5)
We multiply parentheses
2c+2c+10
We add all the numbers together, and all the variables
4c+10
Back to the equation:
-(4c+10)
-2c-(4c+10)+30=0
We get rid of parentheses
-2c-4c-10+30=0
We add all the numbers together, and all the variables
-6c+20=0
We move all terms containing c to the left, all other terms to the right
-6c=-20
c=-20/-6
c=3+1/3
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