33-(2x+3)=4(x+4)+x

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Solution for 33-(2x+3)=4(x+4)+x equation: 



33-(2x+3)=4(x+4)+x

We move all terms to the left:

33-(2x+3)-(4(x+4)+x)=0

We get rid of parentheses

-2x-(4(x+4)+x)-3+33=0



We calculate terms in parentheses: -(4(x+4)+x), so:

4(x+4)+x

We add all the numbers together, and all the variables

x+4(x+4)

We multiply parentheses

x+4x+16

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

-2x-(5x+16)+30=0

We get rid of parentheses

-2x-5x-16+30=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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