33-(6q+15)=15-7(q+2)

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Solution for 33-(6q+15)=15-7(q+2) equation: 



33-(6q+15)=15-7(q+2)

We move all terms to the left:

33-(6q+15)-(15-7(q+2))=0

We get rid of parentheses

-6q-(15-7(q+2))-15+33=0



We calculate terms in parentheses: -(15-7(q+2)), so:

15-7(q+2)

determiningTheFunctionDomain
-7(q+2)+15

We multiply parentheses

-7q-14+15

We add all the numbers together, and all the variables

-7q+1

Back to the equation:

-(-7q+1)



We add all the numbers together, and all the variables

-6q-(-7q+1)+18=0

We get rid of parentheses

-6q+7q-1+18=0

We add all the numbers together, and all the variables

q+17=0

We move all terms containing q to the left, all other terms to the right

q=-17

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