33-5=15+(2x+4x)-5

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Solution for 33-5=15+(2x+4x)-5 equation: 



33-5=15+(2x+4x)-5

We move all terms to the left:

33-5-(15+(2x+4x)-5)=0

We add all the numbers together, and all the variables

-(15+(+6x)-5)+33-5=0

We add all the numbers together, and all the variables

-(15+(+6x)-5)+28=0



We calculate terms in parentheses: -(15+(+6x)-5), so:

15+(+6x)-5

determiningTheFunctionDomain
(+6x)+15-5

We add all the numbers together, and all the variables

(+6x)+10

We get rid of parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

-6x-10+28=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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