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330=2x+2(2/3x)
We move all terms to the left:
330-(2x+2(2/3x))=0
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(2x+2(+2/3x))+330=0
We multiply all the terms by the denominator
-(2x+2(+2+330*3x))=0
We calculate terms in parentheses: -(2x+2(+2+330*3x)), so:We get rid of parentheses
2x+2(+2+330*3x)
We add all the numbers together, and all the variables
2x+2(330*3x+2)
We multiply parentheses
2x+1980x+4
We add all the numbers together, and all the variables
1982x+4
Back to the equation:
-(1982x+4)
-1982x-4=0
We move all terms containing x to the left, all other terms to the right
-1982x=4
x=4/-1982
x=-2/991
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