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333x^2=666
We move all terms to the left:
333x^2-(666)=0
a = 333; b = 0; c = -666;
Δ = b2-4ac
Δ = 02-4·333·(-666)
Δ = 887112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{887112}=\sqrt{443556*2}=\sqrt{443556}*\sqrt{2}=666\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-666\sqrt{2}}{2*333}=\frac{0-666\sqrt{2}}{666} =-\frac{666\sqrt{2}}{666} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+666\sqrt{2}}{2*333}=\frac{0+666\sqrt{2}}{666} =\frac{666\sqrt{2}}{666} =\sqrt{2} $
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