33=-5(a-5)+(1+6a)

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Solution for 33=-5(a-5)+(1+6a) equation: 



33=-5(a-5)+(1+6a)

We move all terms to the left:

33-(-5(a-5)+(1+6a))=0

We add all the numbers together, and all the variables

-(-5(a-5)+(6a+1))+33=0



We calculate terms in parentheses: -(-5(a-5)+(6a+1)), so:

-5(a-5)+(6a+1)

We multiply parentheses

-5a+(6a+1)+25

We get rid of parentheses

-5a+6a+1+25

We add all the numbers together, and all the variables

a+26

Back to the equation:

-(a+26)



We get rid of parentheses

-a-26+33=0

We add all the numbers together, and all the variables

-1a+7=0

We move all terms containing a to the left, all other terms to the right

-a=-7

a=-7/-1

a=+7

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