33=1/2(x+2x+1)(x-4)

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Solution for 33=1/2(x+2x+1)(x-4) equation: 



33=1/2(x+2x+1)(x-4)

We move all terms to the left:

33-(1/2(x+2x+1)(x-4))=0



Domain of the equation: 2(x+2x+1)(x-4))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(3x+1)(x-4))+33=0

We multiply parentheses ..

-(1/2(+3x^2-12x+x-4))+33=0

We multiply all the terms by the denominator


-(1+33*2(+3x^2-12x+x-4))=0



We calculate terms in parentheses: -(1+33*2(+3x^2-12x+x-4)), so:

1+33*2(+3x^2-12x+x-4)

determiningTheFunctionDomain
33*2(+3x^2-12x+x-4)+1

Wy multiply elements

66x(++1

We use the square of the difference formula

66x(+1

Back to the equation:

-(66x(+1)



We add all the numbers together, and all the variables

-(66x1=0

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