33=11+2(m+5)

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Solution for 33=11+2(m+5) equation: 



33=11+2(m+5)

We move all terms to the left:

33-(11+2(m+5))=0



We calculate terms in parentheses: -(11+2(m+5)), so:

11+2(m+5)

determiningTheFunctionDomain
2(m+5)+11

We multiply parentheses

2m+10+11

We add all the numbers together, and all the variables

2m+21

Back to the equation:

-(2m+21)



We get rid of parentheses

-2m-21+33=0

We add all the numbers together, and all the variables

-2m+12=0

We move all terms containing m to the left, all other terms to the right

-2m=-12

m=-12/-2

m=+6

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