33=12r-3(9-r)5

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Solution for 33=12r-3(9-r)5 equation: 



33=12r-3(9-r)5

We move all terms to the left:

33-(12r-3(9-r)5)=0

We add all the numbers together, and all the variables

-(12r-3(-1r+9)5)+33=0



We calculate terms in parentheses: -(12r-3(-1r+9)5), so:

12r-3(-1r+9)5

We multiply parentheses

12r+15r-135

We add all the numbers together, and all the variables

27r-135

Back to the equation:

-(27r-135)



We get rid of parentheses

-27r+135+33=0

We add all the numbers together, and all the variables

-27r+168=0

We move all terms containing r to the left, all other terms to the right

-27r=-168

r=-168/-27

r=6+2/9

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