33=2/3z+11

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Solution for 33=2/3z+11 equation: 



33=2/3z+11

We move all terms to the left:

33-(2/3z+11)=0



Domain of the equation: 3z+11)!=0

z∈R



We get rid of parentheses

-2/3z-11+33=0

We multiply all the terms by the denominator


-11*3z+33*3z-2=0

Wy multiply elements

-33z+99z-2=0

We add all the numbers together, and all the variables

66z-2=0

We move all terms containing z to the left, all other terms to the right

66z=2

z=2/66

z=1/33

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