33=3(n+74)

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Solution for 33=3(n+74) equation: 



33=3(n+74)

We move all terms to the left:

33-(3(n+74))=0



We calculate terms in parentheses: -(3(n+74)), so:

3(n+74)

We multiply parentheses

3n+222

Back to the equation:

-(3n+222)



We get rid of parentheses

-3n-222+33=0

We add all the numbers together, and all the variables

-3n-189=0

We move all terms containing n to the left, all other terms to the right

-3n=189

n=189/-3

n=-63

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