33=3(x+3)+3

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Solution for 33=3(x+3)+3 equation: 



33=3(x+3)+3

We move all terms to the left:

33-(3(x+3)+3)=0



We calculate terms in parentheses: -(3(x+3)+3), so:

3(x+3)+3

We multiply parentheses

3x+9+3

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-3x-12+33=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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