33=3(y+4)-6y

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Solution for 33=3(y+4)-6y equation: 



33=3(y+4)-6y

We move all terms to the left:

33-(3(y+4)-6y)=0



We calculate terms in parentheses: -(3(y+4)-6y), so:

3(y+4)-6y

We add all the numbers together, and all the variables

-6y+3(y+4)

We multiply parentheses

-6y+3y+12

We add all the numbers together, and all the variables

-3y+12

Back to the equation:

-(-3y+12)



We get rid of parentheses

3y-12+33=0

We add all the numbers together, and all the variables

3y+21=0

We move all terms containing y to the left, all other terms to the right

3y=-21

y=-21/3

y=-7

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