33=3c+12

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Solution for 33=3c+12 equation: 



33=3c+12

We move all terms to the left:

33-(3c+12)=0

We get rid of parentheses

-3c-12+33=0

We add all the numbers together, and all the variables

-3c+21=0

We move all terms containing c to the left, all other terms to the right

-3c=-21

c=-21/-3

c=+7

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