33=3x(4x*2)

Solution for 33=3x(4x*2) equation:

33=3x(4x*2)

We move all terms to the left:

33-(3x(4x*2))=0

We add all the numbers together, and all the variables

-(3x(+4x*2))+33=0


We calculate terms in parentheses: -(3x(+4x*2)), so:

3x(+4x*2)

We multiply parentheses

24x^2

Back to the equation:

-(24x^2)


a = -24; b = 0; c = +33;
Δ = b2-4ac
Δ = 02-4·(-24)·33
Δ = 3168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3168}=\sqrt{144*22}=\sqrt{144}*\sqrt{22}=12\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{22}}{2*-24}=\frac{0-12\sqrt{22}}{-48}
=-\frac{12\sqrt{22}}{-48}
=-\frac{\sqrt{22}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{22}}{2*-24}=\frac{0+12\sqrt{22}}{-48}
=\frac{12\sqrt{22}}{-48}
=\frac{\sqrt{22}}{-4}
$