33=3z+(-3)

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Solution for 33=3z+(-3) equation: 



33=3z+(-3)

We move all terms to the left:

33-(3z+(-3))=0



We calculate terms in parentheses: -(3z+(-3)), so:

3z+(-3)

We add all the numbers together, and all the variables

3z-3

Back to the equation:

-(3z-3)



We get rid of parentheses

-3z+3+33=0

We add all the numbers together, and all the variables

-3z+36=0

We move all terms containing z to the left, all other terms to the right

-3z=-36

z=-36/-3

z=+12

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