If it's not what You are looking for type in the equation solver your own equation and let us solve it.
33=5s-(100+2s)
We move all terms to the left:
33-(5s-(100+2s))=0
We add all the numbers together, and all the variables
-(5s-(2s+100))+33=0
We calculate terms in parentheses: -(5s-(2s+100)), so:We get rid of parentheses
5s-(2s+100)
We get rid of parentheses
5s-2s-100
We add all the numbers together, and all the variables
3s-100
Back to the equation:
-(3s-100)
-3s+100+33=0
We add all the numbers together, and all the variables
-3s+133=0
We move all terms containing s to the left, all other terms to the right
-3s=-133
s=-133/-3
s=44+1/3
| 3x+24+2x+21=90 | | x+33+18x=90 | | x-30+38=90 | | 4x+2+10+4x-2=180 | | 63=18+5x | | 2(x+3)+5(x+1)=10+3(x–5) | | -2+y=40 | | x-(8.953(0.3-x)(0.4-x))=0 | | 2x-48+x-15=90 | | 8^x-1=22 | | 13=y+47 | | 29=-66+5x | | 5x-9=79 | | n^{2}+14n-51=0 | | 2c/8=3c | | 15=2xx3x | | 150=2x.3x | | n=63/5=9 | | x*2-28x=0 | | 1;4.4=-2.4b | | X+0.08x=102 | | 2(6*u)+2(16*u)+2(16*6)=1248 | | c–3–3=–20 | | x12=2884 | | 5n-10=7n+10 | | 100√(q)=(2q-1200) | | 3^4x3^x=(3^5)^4 | | 00√(q)=(2q-1200) | | 3/9=15x | | -y+6=5 | | g+10+5+g=25 | | X^+4x=7 |