33=7(u+5)-5u

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Solution for 33=7(u+5)-5u equation:



33=7(u+5)-5u
We move all terms to the left:
33-(7(u+5)-5u)=0
We calculate terms in parentheses: -(7(u+5)-5u), so:
7(u+5)-5u
We add all the numbers together, and all the variables
-5u+7(u+5)
We multiply parentheses
-5u+7u+35
We add all the numbers together, and all the variables
2u+35
Back to the equation:
-(2u+35)
We get rid of parentheses
-2u-35+33=0
We add all the numbers together, and all the variables
-2u-2=0
We move all terms containing u to the left, all other terms to the right
-2u=2
u=2/-2
u=-1

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