33=x/3+35

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Solution for 33=x/3+35 equation: 



33=x/3+35

We move all terms to the left:

33-(x/3+35)=0

We get rid of parentheses

-x/3-35+33=0

We multiply all the terms by the denominator


-x-35*3+33*3=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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