33=y+2(y+3)

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Solution for 33=y+2(y+3) equation: 



33=y+2(y+3)

We move all terms to the left:

33-(y+2(y+3))=0



We calculate terms in parentheses: -(y+2(y+3)), so:

y+2(y+3)

We multiply parentheses

y+2y+6

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

-3y-6+33=0

We add all the numbers together, and all the variables

-3y+27=0

We move all terms containing y to the left, all other terms to the right

-3y=-27

y=-27/-3

y=+9

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