33k2+112k-33=0

Solution for 33k2+112k-33=0 equation:

33k^2+112k-33=0

a = 33; b = 112; c = -33;
Δ = b2-4ac
Δ = 1122-4·33·(-33)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-130}{2*33}=\frac{-242}{66}
=-3+2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+130}{2*33}=\frac{18}{66}
=3/11
$