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33x+3x^2+72=0.
a = 3; b = 33; c = +72;
Δ = b2-4ac
Δ = 332-4·3·72
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*3}=\frac{-48}{6} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*3}=\frac{-18}{6} =-3 $
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