33x+8=(7x+3)+(6x+11)+(7x+3)+x

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Solution for 33x+8=(7x+3)+(6x+11)+(7x+3)+x equation: 



33x+8=(7x+3)+(6x+11)+(7x+3)+x

We move all terms to the left:

33x+8-((7x+3)+(6x+11)+(7x+3)+x)=0



We calculate terms in parentheses: -((7x+3)+(6x+11)+(7x+3)+x), so:

(7x+3)+(6x+11)+(7x+3)+x

We add all the numbers together, and all the variables

x+(7x+3)+(6x+11)+(7x+3)

We get rid of parentheses

x+7x+6x+7x+3+11+3

We add all the numbers together, and all the variables

21x+17

Back to the equation:

-(21x+17)



We get rid of parentheses

33x-21x-17+8=0

We add all the numbers together, and all the variables

12x-9=0

We move all terms containing x to the left, all other terms to the right

12x=9

x=9/12

x=3/4

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