33x2+-52x+20=0

Solution for 33x2+-52x+20=0 equation:

33x^2+-52x+20=0

We add all the numbers together, and all the variables

33x^2-52x=0

a = 33; b = -52; c = 0;
Δ = b2-4ac
Δ = -522-4·33·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-52}{2*33}=\frac{0}{66}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+52}{2*33}=\frac{104}{66}
=1+19/33
$