33x2+8x-1=0

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Solution for 33x2+8x-1=0 equation:



33x^2+8x-1=0
a = 33; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·33·(-1)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-14}{2*33}=\frac{-22}{66} =-1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+14}{2*33}=\frac{6}{66} =1/11 $

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