33y-48=3(6y+4)

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Solution for 33y-48=3(6y+4) equation: 



33y-48=3(6y+4)

We move all terms to the left:

33y-48-(3(6y+4))=0



We calculate terms in parentheses: -(3(6y+4)), so:

3(6y+4)

We multiply parentheses

18y+12

Back to the equation:

-(18y+12)



We get rid of parentheses

33y-18y-12-48=0

We add all the numbers together, and all the variables

15y-60=0

We move all terms containing y to the left, all other terms to the right

15y=60

y=60/15

y=4

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