33y=16(2y+23)

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Solution for 33y=16(2y+23) equation: 



33y=16(2y+23)

We move all terms to the left:

33y-(16(2y+23))=0



We calculate terms in parentheses: -(16(2y+23)), so:

16(2y+23)

We multiply parentheses

32y+368

Back to the equation:

-(32y+368)



We get rid of parentheses

33y-32y-368=0

We add all the numbers together, and all the variables

y-368=0

We move all terms containing y to the left, all other terms to the right

y=368

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