34(2a-6)+12=25(3a+20)

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Solution for 34(2a-6)+12=25(3a+20) equation: 



34(2a-6)+12=25(3a+20)

We move all terms to the left:

34(2a-6)+12-(25(3a+20))=0

We multiply parentheses

68a-(25(3a+20))-204+12=0



We calculate terms in parentheses: -(25(3a+20)), so:

25(3a+20)

We multiply parentheses

75a+500

Back to the equation:

-(75a+500)



We add all the numbers together, and all the variables

68a-(75a+500)-192=0

We get rid of parentheses

68a-75a-500-192=0

We add all the numbers together, and all the variables

-7a-692=0

We move all terms containing a to the left, all other terms to the right

-7a=692

a=692/-7

a=-98+6/7

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