34-(3c+4)=(c+3)+c

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Solution for 34-(3c+4)=(c+3)+c equation: 



34-(3c+4)=(c+3)+c

We move all terms to the left:

34-(3c+4)-((c+3)+c)=0

We get rid of parentheses

-3c-((c+3)+c)-4+34=0



We calculate terms in parentheses: -((c+3)+c), so:

(c+3)+c

We add all the numbers together, and all the variables

c+(c+3)

We get rid of parentheses

c+c+3

We add all the numbers together, and all the variables

2c+3

Back to the equation:

-(2c+3)



We add all the numbers together, and all the variables

-3c-(2c+3)+30=0

We get rid of parentheses

-3c-2c-3+30=0

We add all the numbers together, and all the variables

-5c+27=0

We move all terms containing c to the left, all other terms to the right

-5c=-27

c=-27/-5

c=5+2/5

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