34-4(2w+1)=10-w(10+w)

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Solution for 34-4(2w+1)=10-w(10+w) equation:



34-4(2w+1)=10-w(10+w)
We move all terms to the left:
34-4(2w+1)-(10-w(10+w))=0
We add all the numbers together, and all the variables
-4(2w+1)-(10-w(w+10))+34=0
We multiply parentheses
-8w-(10-w(w+10))-4+34=0
We calculate terms in parentheses: -(10-w(w+10)), so:
10-w(w+10)
determiningTheFunctionDomain -w(w+10)+10
We multiply parentheses
-w^2-10w+10
We add all the numbers together, and all the variables
-1w^2-10w+10
Back to the equation:
-(-1w^2-10w+10)
We add all the numbers together, and all the variables
-(-1w^2-10w+10)-8w+30=0
We get rid of parentheses
1w^2+10w-8w-10+30=0
We add all the numbers together, and all the variables
w^2+2w+20=0
a = 1; b = 2; c = +20;
Δ = b2-4ac
Δ = 22-4·1·20
Δ = -76
Delta is less than zero, so there is no solution for the equation

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