34-4(2w+1)=10-w(10+w)

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Solution for 34-4(2w+1)=10-w(10+w) equation: 



34-4(2w+1)=10-w(10+w)

We move all terms to the left:

34-4(2w+1)-(10-w(10+w))=0

We add all the numbers together, and all the variables

-4(2w+1)-(10-w(w+10))+34=0

We multiply parentheses

-8w-(10-w(w+10))-4+34=0



We calculate terms in parentheses: -(10-w(w+10)), so:

10-w(w+10)

determiningTheFunctionDomain
-w(w+10)+10

We multiply parentheses

-w^2-10w+10

We add all the numbers together, and all the variables

-1w^2-10w+10

Back to the equation:

-(-1w^2-10w+10)



We add all the numbers together, and all the variables

-(-1w^2-10w+10)-8w+30=0

We get rid of parentheses

1w^2+10w-8w-10+30=0

We add all the numbers together, and all the variables

w^2+2w+20=0

a = 1; b = 2; c = +20;
Δ = b2-4ac
Δ = 22-4·1·20
Δ = -76
Delta is less than zero, so there is no solution for the equation

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