34/6=(2r+1)/3

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Solution for 34/6=(2r+1)/3 equation: 



34/6=(2r+1)/3

We move all terms to the left:

34/6-((2r+1)/3)=0

We calculate fractions


(-((2r+1)*6)/()+()/()=0



We calculate terms in parentheses: +(-((2r+1)*6)/()+()/(), so:

-((2r+1)*6)/()+()/(

We add all the numbers together, and all the variables

-((2r+1)*6)/()+1

We multiply all the terms by the denominator


-((2r+1)*6)+1*()



We calculate terms in parentheses: -((2r+1)*6), so:

(2r+1)*6

We multiply parentheses

12r+6

Back to the equation:

-(12r+6)



We add all the numbers together, and all the variables

-(12r+6)

We get rid of parentheses

-12r-6

Back to the equation:

+(-12r-6)



We get rid of parentheses

-12r-6=0

We move all terms containing r to the left, all other terms to the right

-12r=6

r=6/-12

r=-1/2

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