340=(14+2x)(16+2x)

Solution for 340=(14+2x)(16+2x) equation:

340=(14+2x)(16+2x)

We move all terms to the left:

340-((14+2x)(16+2x))=0

We add all the numbers together, and all the variables

-((2x+14)(2x+16))+340=0

We multiply parentheses ..

-((+4x^2+32x+28x+224))+340=0


We calculate terms in parentheses: -((+4x^2+32x+28x+224)), so:

(+4x^2+32x+28x+224)

We get rid of parentheses

4x^2+32x+28x+224

We add all the numbers together, and all the variables

4x^2+60x+224

Back to the equation:

-(4x^2+60x+224)


We get rid of parentheses

-4x^2-60x-224+340=0

We add all the numbers together, and all the variables

-4x^2-60x+116=0

a = -4; b = -60; c = +116;
Δ = b2-4ac
Δ = -602-4·(-4)·116
Δ = 5456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5456}=\sqrt{16*341}=\sqrt{16}*\sqrt{341}=4\sqrt{341}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{341}}{2*-4}=\frac{60-4\sqrt{341}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{341}}{2*-4}=\frac{60+4\sqrt{341}}{-8}
$