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34=(9y-15)(-2/3)
We move all terms to the left:
34-((9y-15)(-2/3))=0
We multiply parentheses ..
-((-18y^2-15*-2/3))+34=0
We multiply all the terms by the denominator
-((-18y^2-15*-2+34*3))=0
We calculate terms in parentheses: -((-18y^2-15*-2+34*3)), so:We get rid of parentheses
(-18y^2-15*-2+34*3)
We get rid of parentheses
-18y^2-2-15*+34*3
We add all the numbers together, and all the variables
-18y^2
Back to the equation:
-(-18y^2)
18y^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{36}=0$
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