34=3(n-5)+1

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Solution for 34=3(n-5)+1 equation:



34=3(n-5)+1
We move all terms to the left:
34-(3(n-5)+1)=0
We calculate terms in parentheses: -(3(n-5)+1), so:
3(n-5)+1
We multiply parentheses
3n-15+1
We add all the numbers together, and all the variables
3n-14
Back to the equation:
-(3n-14)
We get rid of parentheses
-3n+14+34=0
We add all the numbers together, and all the variables
-3n+48=0
We move all terms containing n to the left, all other terms to the right
-3n=-48
n=-48/-3
n=+16

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