34x+95=3x(14x+9)

Solution for 34x+95=3x(14x+9) equation:

34x+95=3x(14x+9)

We move all terms to the left:

34x+95-(3x(14x+9))=0


We calculate terms in parentheses: -(3x(14x+9)), so:

3x(14x+9)

We multiply parentheses

42x^2+27x

Back to the equation:

-(42x^2+27x)


We get rid of parentheses

-42x^2+34x-27x+95=0

We add all the numbers together, and all the variables

-42x^2+7x+95=0

a = -42; b = 7; c = +95;
Δ = b2-4ac
Δ = 72-4·(-42)·95
Δ = 16009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{16009}}{2*-42}=\frac{-7-\sqrt{16009}}{-84}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{16009}}{2*-42}=\frac{-7+\sqrt{16009}}{-84}
$