34x-5=(1/27)2x+10

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Solution for 34x-5=(1/27)2x+10 equation: 



34x-5=(1/27)2x+10

We move all terms to the left:

34x-5-((1/27)2x+10)=0



Domain of the equation: 27)2x+10)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

34x-((+1/27)2x+10)-5=0

We multiply all the terms by the denominator


34x*27)2x+10)-((-5*27)2x+10)+1=0

We add all the numbers together, and all the variables

34x*27)2x+10)-((-135)2x+10)+1=0

Wy multiply elements

918x^2-135)2x+10)+1=0

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