34y=3(11y+11)

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Solution for 34y=3(11y+11) equation: 



34y=3(11y+11)

We move all terms to the left:

34y-(3(11y+11))=0



We calculate terms in parentheses: -(3(11y+11)), so:

3(11y+11)

We multiply parentheses

33y+33

Back to the equation:

-(33y+33)



We get rid of parentheses

34y-33y-33=0

We add all the numbers together, and all the variables

y-33=0

We move all terms containing y to the left, all other terms to the right

y=33

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