35(2c+3)=2(c+6)+c

Solution for 35(2c+3)=2(c+6)+c equation:

35(2c+3)=2(c+6)+c

We move all terms to the left:

35(2c+3)-(2(c+6)+c)=0

We multiply parentheses

70c-(2(c+6)+c)+105=0


We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)


We get rid of parentheses

70c-3c-12+105=0

We add all the numbers together, and all the variables

67c+93=0

We move all terms containing c to the left, all other terms to the right

67c=-93

c=-93/67

c=-1+26/67