35(2c+4)=2(c+3)+c

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Solution for 35(2c+4)=2(c+3)+c equation: 



35(2c+4)=2(c+3)+c

We move all terms to the left:

35(2c+4)-(2(c+3)+c)=0

We multiply parentheses

70c-(2(c+3)+c)+140=0



We calculate terms in parentheses: -(2(c+3)+c), so:

2(c+3)+c

We add all the numbers together, and all the variables

c+2(c+3)

We multiply parentheses

c+2c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

70c-3c-6+140=0

We add all the numbers together, and all the variables

67c+134=0

We move all terms containing c to the left, all other terms to the right

67c=-134

c=-134/67

c=-2

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