35(2x+3)-2=-2+34(3-2x)

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Solution for 35(2x+3)-2=-2+34(3-2x) equation:



35(2x+3)-2=-2+34(3-2x)
We move all terms to the left:
35(2x+3)-2-(-2+34(3-2x))=0
We add all the numbers together, and all the variables
35(2x+3)-(-2+34(-2x+3))-2=0
We multiply parentheses
70x-(-2+34(-2x+3))+105-2=0
We calculate terms in parentheses: -(-2+34(-2x+3)), so:
-2+34(-2x+3)
determiningTheFunctionDomain 34(-2x+3)-2
We multiply parentheses
-68x+102-2
We add all the numbers together, and all the variables
-68x+100
Back to the equation:
-(-68x+100)
We add all the numbers together, and all the variables
70x-(-68x+100)+103=0
We get rid of parentheses
70x+68x-100+103=0
We add all the numbers together, and all the variables
138x+3=0
We move all terms containing x to the left, all other terms to the right
138x=-3
x=-3/138
x=-1/46

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