35(3x-7)=21(12x+4)

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Solution for 35(3x-7)=21(12x+4) equation: 



35(3x-7)=21(12x+4)

We move all terms to the left:

35(3x-7)-(21(12x+4))=0

We multiply parentheses

105x-(21(12x+4))-245=0



We calculate terms in parentheses: -(21(12x+4)), so:

21(12x+4)

We multiply parentheses

252x+84

Back to the equation:

-(252x+84)



We get rid of parentheses

105x-252x-84-245=0

We add all the numbers together, and all the variables

-147x-329=0

We move all terms containing x to the left, all other terms to the right

-147x=329

x=329/-147

x=-2+5/21

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