35+(4b-50)+(2b-21)=180

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Solution for 35+(4b-50)+(2b-21)=180 equation: 



35+(4b-50)+(2b-21)=180

We move all terms to the left:

35+(4b-50)+(2b-21)-(180)=0

We add all the numbers together, and all the variables

(4b-50)+(2b-21)-145=0

We get rid of parentheses

4b+2b-50-21-145=0

We add all the numbers together, and all the variables

6b-216=0

We move all terms containing b to the left, all other terms to the right

6b=216

b=216/6

b=36

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