35+2n=4n-5(n-7)

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Solution for 35+2n=4n-5(n-7) equation: 



35+2n=4n-5(n-7)

We move all terms to the left:

35+2n-(4n-5(n-7))=0



We calculate terms in parentheses: -(4n-5(n-7)), so:

4n-5(n-7)

We multiply parentheses

4n-5n+35

We add all the numbers together, and all the variables

-1n+35

Back to the equation:

-(-1n+35)



We get rid of parentheses

2n+1n-35+35=0

We add all the numbers together, and all the variables

3n=0

n=0/3

n=0

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