35+2n=8(4n-4)=7

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Solution for 35+2n=8(4n-4)=7 equation: 



35+2n=8(4n-4)=7

We move all terms to the left:

35+2n-(8(4n-4))=0



We calculate terms in parentheses: -(8(4n-4)), so:

8(4n-4)

We multiply parentheses

32n-32

Back to the equation:

-(32n-32)



We get rid of parentheses

2n-32n+32+35=0

We add all the numbers together, and all the variables

-30n+67=0

We move all terms containing n to the left, all other terms to the right

-30n=-67

n=-67/-30

n=2+7/30

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