35+3(10-x)=5(x-1)

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Solution for 35+3(10-x)=5(x-1) equation: 



35+3(10-x)=5(x-1)

We move all terms to the left:

35+3(10-x)-(5(x-1))=0

We add all the numbers together, and all the variables

3(-1x+10)-(5(x-1))+35=0

We multiply parentheses

-3x-(5(x-1))+30+35=0



We calculate terms in parentheses: -(5(x-1)), so:

5(x-1)

We multiply parentheses

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

-3x-(5x-5)+65=0

We get rid of parentheses

-3x-5x+5+65=0

We add all the numbers together, and all the variables

-8x+70=0

We move all terms containing x to the left, all other terms to the right

-8x=-70

x=-70/-8

x=8+3/4

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