35+3b=-6(b-5)+4b

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Solution for 35+3b=-6(b-5)+4b equation: 



35+3b=-6(b-5)+4b

We move all terms to the left:

35+3b-(-6(b-5)+4b)=0



We calculate terms in parentheses: -(-6(b-5)+4b), so:

-6(b-5)+4b

We add all the numbers together, and all the variables

4b-6(b-5)

We multiply parentheses

4b-6b+30

We add all the numbers together, and all the variables

-2b+30

Back to the equation:

-(-2b+30)



We get rid of parentheses

3b+2b-30+35=0

We add all the numbers together, and all the variables

5b+5=0

We move all terms containing b to the left, all other terms to the right

5b=-5

b=-5/5

b=-1

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